Answer
$3.65\times 10^{-17}W$
Work Step by Step
We know that
$P=(\frac{N}{t})(\frac{hc}{\lambda})$
We plug in the known values to obtain:
$P=(\frac{100photons}{1s})(\frac{(6.63\times 10^{-34}J.s)(3\times 10^8m/s)}{545\times 10^{-9}m})$
$P=3.65\times 10^{-17}W$
