Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 30 - Quantum Physics - Problems and Conceptual Exercises - Page 1076: 71

Answer

$ 1.4\times 10^{-20}Kg\frac{m}{s}$

Work Step by Step

According to Heisneberg's principle $\Delta p.\Delta y\geq\frac{h}{2\pi}$ We plug in the known values to obtain: $\Delta p\times 7.5\times 10^{-15}\geq 1.055\times 10^{-34}$ $\Delta p\geq 1.4\times 10^{-20}Kg\frac{m}{s}$
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