Answer
$1.8\times 10^{-25}J$
Work Step by Step
According to Heisenberg's principle
$\Delta E.\Delta t\geq\frac{h}{2\pi}$
We plug in the known values to obtain:
$0.6\times 10^{-9}\times \Delta E\geq\frac{6.63\times 10^{-34}}{2\pi}$
$\implies 0.6\times 10^{-9}\times \Delta E\geq 1.055\times 10^{-34}$
$\Delta E\geq 1.8\times 10^{-25}J$
