Answer
$ \Delta y\geq 1.84\times 10^{-31}m$
Work Step by Step
According to Heisenberg's principle
$\Delta p.\Delta y\geq\frac{h}{2\pi}$
$\implies m\Delta v.\Delta y\geq\frac{h}{2\pi}$
We plug in the known values to obtain:
$0.26\times 0.0022\times \Delta y \geq\frac{6.63\times 10^{-34}}{2\pi}$
$5.72\times 10^{-4}\times \Delta y\geq1.055\times 10^{-34} $
$\implies \Delta y\geq 1.84\times 10^{-31}m$
