Answer
(a) $1.34\times 10^{-35}m/s$
(b) $7.45\times 10^{31}s$
Work Step by Step
(a) We know that
$v=\frac{h}{m\lambda}$
We plug in the known values to obtain:
$v=\frac{6.63\times 10^{-34}}{(65)(0.76)}$
$v=1.34\times 10^{-35}m/s$
(b) We can find the required time as
$x=\frac{h}{m\lambda}t$
This can be rearranged as:
$x=\frac{(65)(0.76)(1.0\times 10^{-3})}{6.63\times 10^{-34}}$
$x=7.45\times 10^{31}s$
