Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 941: 43

Answer

$d_{\circ}=1.4m; d_i=0.48m$

Work Step by Step

We can find the object distance as follows: $\frac{1}{f}=\frac{1}{d_{\circ}}+\frac{1}{d_i}$ We plug in the known values to obtain: $\frac{1}{36cm}=\frac{1}{d_{\circ}}+\frac{1}{\frac{d_{\circ}}{3}}$ This simplifies to: $d_{\circ}=4(36cm)=144.0cm=1.4m$ Now we can find the distance of the image as follows: $d_i=\frac{d_{\circ}}{3}$ We plug in the known values to obtain: $d_i =\frac{144cm}{3}=48cm=0.48m$
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