Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 941: 51

Answer

$1.82$

Work Step by Step

The required ratio can be determined as $\frac{v_w}{v_d}=\frac{c/n_w}{c/n_d}$ $\implies\frac{v_w}{v_d}=\frac{n_d}{n_w} $ We plug in the known values to obtain: $\frac{v_w}{v_d}=\frac{2.42}{1.33}=1.82$
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