Answer
(a) $4.2cm$
(b) $11cm$
Work Step by Step
(a) We know that
$\frac{1}{d_i}=-\frac{4}{D}-\frac{1}{d_{\circ}}$
We plug in the known values to obtain:
$\frac{1}{d_i}=-\frac{4}{0.18m}-\frac{1}{0.66m}$
This simplifies to:
$d_i=-0.042m=-4.2cm$
The imaged will be formed behind the globe.
(b) We can find the required height of the image as follows:
$h_i=(-\frac{d_i}{d_{\circ}})h_{\circ}$
We plug in the known values to obtain:
$h_i=[-\frac{(-0.042m)}{0.66m}](1.7m)$
$h_i=0.1081m=11cm$
