Answer
(a) upright
(b) $3.508feet$
Work Step by Step
(a) We know that the image produced by the convex mirror is always upright.
(b) We know that
$h_i=6.4inches\times \frac{1feet}{12inches}=0.533feet$
Now we can find the required radius of curvature as follows:
$R=-(\frac{2}{\frac{1}{d_{\circ}}(1-\frac{1}{m})})$
We plug in the known values to obtain:
$R=-(\frac{2}{(0.0588)(-9.69)})$
$R=3.508feet$
