Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 941: 39

Answer

$-9.0cm,12cm$

Work Step by Step

(a) We can find the image distance as $d_i=-md_{\circ}$ We plug in the known values to obtain: $d_i=-(\frac{1}{4})(36cm)=-9.0cm$ (b) We can find the focal length as $f=(\frac{1}{d_{\circ}}+\frac{1}{d_i})^{-1}$ We plug in the known values to obtain: $f=(\frac{1}{36}+\frac{1}{-9.0cm})^{-1}$ $f=-12cm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.