Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 940: 15

Answer

$23cm$

Work Step by Step

We know that $\theta=\frac{27}{2}=13.5^{\circ}$ Now we can find the required distance as follows: $tan\theta=\frac{y}{d}$ We plug in the known values to obtain: $tan 13.5^{\circ}=\frac{5.5cm}{d}$ This simplifies to: $d=23cm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.