Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 940: 16

Answer

$10Km$

Work Step by Step

We know that $\theta=2(45.001-45.000)=0.002^{\circ}$ Now $tan\theta=\frac{y}{x}$ This can be rearranged as: $y=xtan\theta$ We plug in the known values to obtain: $y=(3.84\times 10^5Km)tan(0.002^{\circ})$ $y=10Km$
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