Answer
$1.15m$
Work Step by Step
We can find the required height as follows:
$h=\frac{\frac{x_t}{x_p}h_p+h_t}{1+\frac{x_t}{x_p}}$
We plug in the known values to obtain:
$h=\frac{(\frac{1.5m}{3.2m})(1.9m)+0.80m}{1+\frac{1.5m}{3.2m}}$
$h=1.15m$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 940: 12
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