Answer
(a) $63cm$, $-12.07cm$
(b) inverted
Work Step by Step
(a) We know that the image distance is given as
$d_i=\frac{f(d_{\circ})}{d_{\circ}-f}$
We plug in the known values to obtain:
$d_i=\frac{(0.50m)(2.4m)}{2.4m-0.50m}$
$\implies d_i=0.631m$
$\implies d_i=63cm$
Now the height of the image is given as
$h_i=(-\frac{d_i}{d_{\circ}})(h_{\circ})$
We plug in the known values to obtain:
$h_i=-\frac{63cm}{240cm}(46cm)$
$\implies h_i=-12.07cm$
Th image is formed on the same side of the object.
(b) We know that the image is formed just before the concave mirror and the image is inverted.
