Answer
(a) $2.6m/s$ (b) $2.0m/s$
Work Step by Step
(a) Since the distance from the mirror to the object is equal to the distance from the mirror to the image, and the person is walking directly towards the mirror, the velocity of the image must be the same, $2.6m/s$. (b) To find the change in distance, draw a triangle with components. The component pointing toward the mirror is the y-component, which is equal to $$v_y=vcos\theta$$ Substituting known values of $v=2.6m/s$ and $\theta=38^{\circ}$ yields a velocity of $$v_y=(2.6m/s)cos(38^{\circ})=2.0m/s$$
