Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 940: 13

Answer

$33cm$ wide and $7.5cm$ high

Work Step by Step

We can determine the required dimensions as follows: First we find the width $w=\frac{W_w x_e}{x_e+x_w}$ We plug in the known values to obtain: $w=\frac{(1.3m)(0.50m)}{0.50m+1.50m}$ $\implies w=33m=33cm$ Now the height can be calculated as $h=\frac{x_wx_e}{x_e+x_w}$ We plug in the known values to obtain: $h=\frac{(0.30m)(0.50m)}{0.50m+1.50m}$ $\implies h=0.075m=7.5cm$
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