Answer
$45.2\Omega$
Work Step by Step
We know that
$L=\frac{X_L}{\omega}$
We plug in the known values to obtain:
$L=\frac{56.5}{2\pi(75.0)}=0.1199H$
Now $X_L=2\pi(60.0)(0.1199)=45.2\Omega$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 868: 29
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