Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 868: 19

Answer

$53.4\Omega$

Work Step by Step

We can find the impedance as follows: $Z=\sqrt{R^2+(\frac{1}{\omega C})^2}$ We plug in the known values to obtain: $Z=\sqrt{(45.5)^2+[\frac{1}{2\pi (60.0)(95.0)}]^2}$ $Z=53.4\Omega$
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