Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 868: 30

Answer

$3.93 A$

Work Step by Step

As $X_L=\omega L=2\pi fL$ We plug in the known values to obtain: $X_L=2\pi*60*(77.5*10^{-3})=29.22\Omega$ Now $I_{rms}=\frac{V_{rms}}{29.22}=3.93 A$
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