Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 868: 38

Answer

Please see the work below.

Work Step by Step

(a) We know that $f=\frac{1}{2\pi L}[(\frac{V_{rms}}{I_{rms}})^2-R^2]^{\frac{1}{2}}$ We plug in the known values to obtain: $f=\frac{1}{2\pi\times 31\times 10^{-3}}[(\frac{120}{1.5})^2-(68)^2]^{\frac{1}{2}}$ This simplifies to: $f=216Hz$ (b) As $V_{rms, R}=I_{rms}\times R$ We plug in the known values to obtain: $V_{rms, R}=1.5\times 68$ $V_{rms,R}=102V$ (c) We know that $V_{rms, L}=I_{rms}\times X_L$ $V_{rms,L}=1.5\times 2\pi fL$ We plug in the known values to obtain: $V_{rms,L}=1.5\times 2\pi\times 216\times 31\times 10^{-3}$ $V_{rms,L}=63V$ (d) As $\sqrt{V^2_{rms,R}+V^2_{rms,L}}=\sqrt{(102)^2+(63)^2}$ $\sqrt{V^2_{rms,R}+V^2_{rms,L}}=\sqrt{10404+3969}=120V$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.