Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 868: 18

Answer

$f=157.8Hz$

Work Step by Step

We can find the required frequency as follows: $f=\frac{I_{rms}}{2\pi CV_{rms}}$ We plug in the known values to obtain: $f=\frac{7.5\times 10^{-3}}{2\pi \times 0.015\times 10^{-6}\times 504}$ $f=157.8Hz$
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