Answer
$37.3mA$
Work Step by Step
The required rms current can be determined as follows:
$Z=\sqrt{R^2+(2\pi fL)^2}$
We plug in the known values to obtain:
$Z=\sqrt{(525)^2+(2\pi(60)(295\times 10^{-3}))^2}$
$Z=536.63\Omega$
Now $I_{rms}=\frac{V_{rms}}{Z}$
We plug in the known values to obtain:
$I_{rms}=\frac{20.0V}{563.3\Omega}$
$I_{rms}=37.3\times 10^{-3}=37.3mA$
