Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 717: 6

Answer

$\Delta U=-25,500eV$

Work Step by Step

We know that $\Delta U=q_{\circ}\Delta V$ We plug in the known values to obtain: $\Delta U=(-e)(25,500)$ $\Delta U=-25,500eV$ $\Delta U=-25,500eV\times 1.6\times 10^{-19}\frac{J}{eV}$ $\Delta U=4.08\times 10^{-15}J$
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