Answer
$\Delta U=-25,500eV$
Work Step by Step
We know that
$\Delta U=q_{\circ}\Delta V$
We plug in the known values to obtain:
$\Delta U=(-e)(25,500)$
$\Delta U=-25,500eV$
$\Delta U=-25,500eV\times 1.6\times 10^{-19}\frac{J}{eV}$
$\Delta U=4.08\times 10^{-15}J$