Answer
$110\frac{m}{s}$
Work Step by Step
We know that
$q\Delta V=\frac{1}{2}mv^2$
This simplifies to:
$v=\sqrt{\frac{2q\Delta V}{m}}$
We plug in the known values to obtain:
$v=\sqrt{\frac{2(7.5\times 10^5)(12)}{1400}}$
$v=110\frac{m}{s}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 717: 13
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