Answer
(a) $0V$
(b) $-4.1\times 10^6V$
(c) $-4.1\times 10^6V$
Work Step by Step
(a) We know that
$\Delta V=-E\Delta s$
We plug in the known values to obtain:
$\Delta V=-(6.8\times 10^5N/C)(0m-0m)$
$\Delta V=0V$
(b) We know that
$\Delta V=-E\Delta s$
We plug in the known values to obtain:
$\Delta V=-(6.8\times 10^5N/C)(6.0m-0m)$
$\Delta V=-4.1\times 10^6V$
(c) We know that
$\Delta V=-(6.8\times 10^5N/C)(6.0m-0m)$
$\Delta V=-4.1\times 10^6V$