Answer
(a) $515V$
(b) $183eV$
Work Step by Step
(a) We can find the electric potential at point C as follows:
$U_C=2U_A-U_B$
$\implies -eV_C=2(-eV_A)-(-eV_B)$
This simplifies to:
$V_C=2V_A-V_B$
$\implies V_C=2(332V)-(149V)$
$\implies V_C=515V$
(b) We can find the required kinetic energy as follows:
$K_A=-eV_A-(-eV_C)$
$\implies K_A=e(V_C-V_A)$
We plug in the known values to obtain:
$K_A=e(515V_332V)$
$\implies K_A=183eV$
