Answer
a) $W=1.1\times 10^{-20}J$
b) same
Work Step by Step
(a) We can find the required work done as follows:
$W=q\Delta V$
We plug in the known values to obtain:
$W=(1.6\times 10^{-19})(0.070)$
$W=1.1\times 10^{-20}J$
(b) As we can see in part(a), the work done is independent of the thickness of the cell membrane. Thus, if the thickness of the cell membrane is increased, then the answer to part(a) will stay the same.
