Answer
$h=10.0m$
Work Step by Step
We can find the required depth as follows:
$h=\frac{P_{at}}{\rho g}$
We plug in the known values to obtain:
$h=\frac{1.01\times 10^5Pa}{(1025Kg/m^3)(9.81m/s^2)}$
$h=10.0m$
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