Answer
$16\frac{m}{s}$
Work Step by Step
We know that
$P_1+\frac{1}{2}\rho_{air}v^2=P_2$
This can be rearranged as:
$P_2-P_1=\frac{1}{2}\rho_{air}v^2$
$\implies \rho_wgh=\frac{1}{2}\rho_{air}v^2$
This can be rearranged as:
$v=\sqrt{\frac{2\rho_{w}gh}{\rho_{air}}}$
We plug in the known values to obtain:
$v=\sqrt{\frac{2(1000)(9.81)(0.016)}{1.29}}=16\frac{m}{s}$
