Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 535: 86

Answer

(a) $1.40W$ (b) $121KJ$ (c) $171m$

Work Step by Step

(a) We can find the power of the heart as $P=(133\frac{N}{cm^2})(105\frac{cm^3}{s})(\frac{1m}{100cm})=1.40W$ (b) The energy expanded by the heart in a day is given as $E=Pt$ We plug in the known values to obtain: $E=(1.40W)(3600\frac{s}{hr})(24\frac{hr}{day})=121KJ$ (c) We know that $E=mgh$ This can be rearranged as $h=\frac{E}{mg}$ We plug in the known values to obtain: $h=\frac{1.21\times 10^5}{(72)(9.81)}=171m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.