Answer
$904\frac{m}{s},2.64$ times the speed of sound.
Work Step by Step
We know that
$v_2=\sqrt{\frac{2(P_1-P_2)}{\rho}}$
We plug in the known values to obtain:
$v_2=\sqrt{\frac{2(59500-1.47)}{1000}(\frac{1.01\times 10^5}{14.7psi})}=904\frac{m}{s}$
Now $\frac{v_2}{v_1}=\frac{904}{343}=2.64$ times the speed of sound.
