Answer
$1.25\times 10^5Pa$
Work Step by Step
The pressure in the pipe can be determined as
$P_1+\rho gy_1=P_2+\rho gy_2$
$\implies P_1=P_{atm}+\rho gy_2$
We plug in the known values to obtain:
$P_1=1.01\times 10^5+(1000)(9.81)(8.0ft)(\frac{1m}{3.28ft})$
$P_1=1.25\times 10^5Pa$
