Answer
(a) $8Km$
(b) zero
Work Step by Step
(a) We know that
$P_{atm}=0+\rho_{air}gh$
We plug in the known values to obtain:
$1.01\times 10^5N/m^2=(1.3Kg/m^3)(9.81m/s^2)h$
This simplifies to:
$h=7900\approx 8Km$
(b) We know that the height of the Everest summit is
$h=(29035ft)(\frac{1m}{3.281ft})$
$h=8849.4m=8.8494Km$
Since this is larger than the result in (a), the atmospheric pressure at Everest summit will be zero. However, our model is imperfect and the true air pressure at Everest summit is greater than zero.
