Answer
$988m/s$
Work Step by Step
The initial speed of the projectile can be determined as:
$v=\sqrt{2GM_M)(\frac{1}{R_M}-\frac{1}{R_M+h})}$
We plug in the known values to obtain:
$v=\sqrt{2(6.67\times 10^{-11})(7.35\times 10^{22})(\frac{1}{1.74\times 10^6}-\frac{1}{1.74\times 10^6+365\times 10^3})}$
$v=988m/s$
