Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 411: 49

Answer

$v=5.03\frac{Km}{s}$

Work Step by Step

As we know that $v=\sqrt{\frac{2GM_m}{R_m}}$ We plug in the known values to obtain: $v=\sqrt{\frac{2(6.67\times 10^{-11})(0.108\times 5.97\times 10^{24})}{3.394\times 10^6}}$ $v=5030\frac{m}{s}$ $v=5.03\frac{Km}{s}$
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