Answer
$4.25\frac{Km}{s}$
$10.4\frac{Km}{s}$
Work Step by Step
(a) We can find the escape velocity for Mercury as
$v=\sqrt{\frac{2GM_M}{R_M}}$
We plug in the known values to obtain:
$v=\sqrt{\frac{2(6.67\times 10^{-11})(0.0553\times 5.97\times 10^{24})}{2.44\times 10^6}}$
$v=4250\frac{m}{s}$
$v=4.25\frac{Km}{s}$
(b) We can find the escape velocity for Venus as
$v=\sqrt{\frac{2GM_V}{R_V}}$
We plug in the known values to obtain:
$v=\sqrt{\frac{2(6.67\times 10^{-11})(0.816\times 5.97\times 10^{24})}{6.052\times 10^6}}$
$v=10400\frac{m}{s}$
$v=10.4\frac{Km}{s}$
