Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 411: 40

Answer

$\ \Delta U=-4.94\times 10^8J$

Work Step by Step

We can find the difference in potential energy as $\Delta U=U_{}-U_{}$ $\Delta U=-G\frac{M_Em}{r_p}-(-G\frac{M_E m}{r_a})$ $\Delta U=GM_Em(\frac{1}{r_a}-\frac{1}{r_p})$ We plug in the known values to obtain: $\Delta U=(6.67\times 10^{-11})(5.97\times 10^{24})(83.5)(\frac{1}{7330\times 10^3}-\frac{1}{6610\times 10^3})$ $\implies \Delta U=-4.94\times 10^8J$
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