Answer
$v=4.30\frac{Km}{s}$
Work Step by Step
We can find the required speed as below
$v=\frac{\pi d}{T}$
We plug in the known values to obtain:
$v=\frac{3.1416\times 3.45\times 10^{12}}{2.52\times 10^9}$
$v=4.30\frac{Km}{s}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 411: 39
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