Answer
$2.69\times10^{25}molecules/m^3$.
Work Step by Step
At STP, 1 mole of ideal gas occupies 22.4 L.
$$\frac{1mole}{22.4L}\frac{6.02\times10^{23}molecules}{mole}\frac{1L}{10^{-3}m^3}=2.69\times10^{25}molecules/m^3$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 13 - Temperature and Kinetic Theory - Problems - Page 387: 38
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