Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 13 - Temperature and Kinetic Theory - Problems - Page 387: 48

Answer

$43.9^{\circ}C$

Work Step by Step

The rms speed is given by equation 13–9. Use kelvins to measure the temperatures. $$\frac{v_{rms,2}}{v_{rms,1}}=1.040=\frac{\sqrt{3kT_2/m}}{\sqrt{3kT_1/m}}=\sqrt{\frac{T_2}{T_1}}$$ $$T_2=T_1(1.04)^2=(293.15K)(1.040)^2=317.07K=43.9^{\circ}C$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.