Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 13 - Temperature and Kinetic Theory - Problems - Page 387: 39

Answer

55.51 mol $3.342\times10^{25}molecules$

Work Step by Step

Assume that the water’s density is $1000\frac{kg}{m^3}$. $$1.000L\frac{10^{-3}m^3}{1L}\frac{1000kg}{1m^3}\frac{1mol}{(15.999+2(1.008))\times10^{-3}kg}=55.51mol$$ $$55.51mol\frac{6.02\times10^{23}molecules}{mole}=3.342\times10^{25}molecules$$
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