Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 13 - Temperature and Kinetic Theory - Problems - Page 387: 31

Answer

0.074, or 7.4 percent of the original air.

Work Step by Step

Use the ideal gas model for air. The volume of the tire remains constant. Let “1” denote the situation before, and “2” denote the situation after. $$PV=n_1RT_1$$ $$PV=n_2RT_2$$ $$\frac{n_2}{n_1}=\frac{T_1}{T_2}=\frac{273.15+15}{273.15+38}=0.926$$ The fraction that must be removed is 1-0.926 = 0.074.
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