Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 917: 35

Answer

D. $P> Q>T>R=S$

Work Step by Step

Since all bulbs are same(resistance) so brightness will be proportional to potential difference across bulb. potential difference across each bulb is $V_P = \frac{5 }{8 }\varepsilon$ $V_Q= \frac{ 3}{ 8}\varepsilon$ $V_R = \frac{ 1}{ 8}\varepsilon$ $V_S = \frac{ 1}{ 8}\varepsilon$ $V_T = \frac{ 2}{8 }\varepsilon$ hence order of brightness i $P> Q>T>R=S$
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