Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 917: 46

Answer

$ \varepsilon = 60V$

Work Step by Step

we have $3.0A = \frac{\varepsilon} {R}.................(i)$ And $2.0A = \frac{\varepsilon}{R+10} ........(ii)$ dividind $(i)$ by $(ii)$ $ 1.5 =1+ \frac{10\Omega}{R}$ $0.5 R = 10\Omega$ $R = 20\Omega$ substituting value of $R$ in $(i)$ $ \varepsilon = 3.0A * R = (3.0 * 20)V$ $ \varepsilon = 60V$
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