Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 917: 41

Answer

$R_{eq}=7\Omega$

Work Step by Step

$10\Omega$ resistor is short circuited, so there is no current through it and it will not be counted for net resistance of circuit now, $4\Omega$, $12\Omega$ and $6\Omega$ are in parallel and their equivalent resistance will be equal to $2\Omega$ now, $2\Omega$,$2\Omega$ and $3\Omega$ are in series $R_{eq} = 2\Omega + 2\Omega + 3\Omega$ $R_{eq}=7\Omega$
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