Answer
$R_{eq}=7\Omega$
Work Step by Step
$10\Omega$ resistor is short circuited, so there is no current through it and it will not be counted for net resistance of circuit
now, $4\Omega$, $12\Omega$ and $6\Omega$ are in parallel and their equivalent resistance will be equal to $2\Omega$
now, $2\Omega$,$2\Omega$ and $3\Omega$ are in series
$R_{eq} = 2\Omega + 2\Omega + 3\Omega$
$R_{eq}=7\Omega$