Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 917: 42

Answer

$P =0.375W$

Work Step by Step

Applying kirchofs law $ 12V- 0.25A * 12\Omega - 0.25A* 6\Omega -6V - 0.25A*R =0$ $12V -3V - 1.5V -6V = 0.25A*R$ $R= 6\Omega$ Power dissipated is $P = I^2 R = (0.25)^2 * 6 W$ $P =0.375W$
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