Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 917: 51

Answer

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Work Step by Step

For the fluorescent bulb, the cost of 10,000 h is given by $${\rm Cost}_{\rm fluorescent }=\$ 5+(0.015){\rm kW}\cdot (0.10){\rm\$ /kW\;h}\cdot (10,000)\;\rm h$$ where $\$ 5$ is the price of one fluorescent bulb. Thus, $${\rm Cost}_{\rm fluorescent }=\$\color{red}{\bf 20} $$ For the ordinary incandescent bulb, the cost of 10,000 h means we need 10 bulbs since the one remains working for only 1000 h. Thus, $${\rm Cost}_{\rm incandescent }=(\$ 0.5)(10)+(0.060){\rm kW}\cdot (0.10){\rm\$ /kW\;h}\cdot (1000)\;\rm h$$ where $\$ 0.5$ is the price of one incandescent bulb. Thus, $${\rm Cost}_{\rm incandescent }=\$\color{red}{\bf 65} $$ So we had to use the fluorescent bulb.
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