Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 916: 34

Answer

C. $P>S=T> Q=R$

Work Step by Step

since all bulbs are same(resistance) so brightness will be proportional to potential difference across bulb. potential difference across each bulb is $V_P =\frac{2}{3}V$ $V_R =\frac{1}{3}V$ $V_Q =\frac{1}{3}V$ $V_S =\frac{1}{2}V$ $V_T =\frac{1}{2}V$ hence order of brightness is $P>S=T> Q=R$
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