Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 30 - Current and Resistance - Exercises and Problems - Page 887: 29

Answer

Tungsten.

Work Step by Step

To identify the material, we need to find its resistivity. We know that the resistance is given by $$R=\dfrac{\rho L}{A}=\dfrac{\rho L}{\pi r^2}$$ Hence, the resistivity is given by $$\rho= \dfrac{\pi r^2R }{ L}$$ Plug the known; $$\rho= \dfrac{\pi (0.4\times 10^{-3})^2(1.1) }{ 10}=\bf 5.53\times 10^{-8}\;\rm \Omega\cdot m$$ Searching in Table 30.2 at the resistivity part to find a match. It is obvious that it is $\color{red}{\bf Tungsten}$.
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