Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 30 - Current and Resistance - Exercises and Problems - Page 887: 25

Answer

Tungsten.

Work Step by Step

To identify the metal, we need to find its conductivity. We know that the current density is given by $$J=\sigma E=\dfrac{I}{A}$$ So, $$\sigma=\dfrac{I}{EA}$$ Plug the known; $$\sigma=\dfrac{(9)}{( 0.0050)(1\times 10^{-4})}$$ Noting that the cross-sectional area of a cube is the same from any direction. $$\sigma=\bf 1.8\times 10^7\;\rm \Omega^{-1}\cdot m^{-1}$$ Searching in Table 30.2 for the conductivities to find a match. It is obvious that it is $\color{red}{\bf Tungsten}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.